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5k^2+17k+11=0
a = 5; b = 17; c = +11;
Δ = b2-4ac
Δ = 172-4·5·11
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{69}}{2*5}=\frac{-17-\sqrt{69}}{10} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{69}}{2*5}=\frac{-17+\sqrt{69}}{10} $
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